Power Factor Calculator

Calculate power factor, reactive power, and phase angle for motors and other AC loads. Understand the efficiency impact on your system.

W
VA
Power factor
PF = 0.800
RatingFair (0.70-0.85) — consider PF correction
Real power (active)800 W
Apparent power1,000 VA
Reactive power600 VAR
Phase angle36.9°
Current increase vs PF=11.25x (25% more current)
Wiring loss increase56% more I²R losses
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How to Use This Calculator

Choose your input method

Select whether to calculate from real watts + apparent VA (if you have both values from a spec sheet) or from voltage + current measurements (from a clamp meter). For V&I mode, also enter the real watts if known — otherwise the calculator assumes 0.8 PF.

Enter your values

For the power input method: real power (W) is what the device spec sheet lists as power consumption or what a true-watt meter reads. Apparent power (VA) is voltage × current, found on UPS units, motor nameplates, and generator ratings. For motors, the nameplate kVA rating is apparent power.

Read the results

The result shows your power factor (0 to 1.0), reactive power in VAR, phase angle in degrees, and the efficiency impact — how much more current (and thus wiring losses) result from operating at your PF versus an ideal PF of 1.0.

The Formula

Power Factor (PF) = Real power (W) ÷ Apparent power (VA) Reactive power (VAR) = √(VA² − W²) Phase angle (θ) = arccos(PF) Current increase = 1 ÷ PF Wiring loss increase (%) = (1 ÷ PF² − 1) × 100

Power factor represents how efficiently current is being used to do real work. A PF of 0.8 means 80% of the apparent power (VA) is doing useful work; the remaining 20% is reactive power circulating in the system. This reactive power doesn't do work but does flow through wires and transformers, causing extra heating and losses.

Example

Three-phase AC unit — understanding PF impact

A commercial AC unit draws 2,000 VA at 1,400W real power. What is the power factor and efficiency impact?

Real power1,400 W
Apparent power2,000 VA
Power factor0.70
Reactive power1,428 VAR
Phase angle45.6°

Efficiency impact

Current vs PF=1 load1.43x more current
Wiring losses increase+104% I²R losses

At PF 0.70, the AC unit draws 43% more current than a purely resistive 1,400W load would. This doubles the resistive wiring losses and means you need larger wire to avoid excessive voltage drop. A power factor correction capacitor bank could bring PF to 0.95+, reducing current draw and losses significantly — cost-effective for commercial installations with multiple motor loads.

FAQ

Power factor is the ratio of real power (doing useful work) to apparent power (total electrical power flowing). In solar systems, low PF loads like motors and compressors cause higher current draw, requiring larger wire sizes and reducing the effective capacity of your inverter. A 3,000W inverter driving a PF 0.7 load can only deliver 2,100W of real work. Modern grid-tied inverters typically operate at 0.95-0.99 PF themselves.
Inductive loads cause low (lagging) power factor — electric motors, transformers, fluorescent light ballasts, and welders. The magnetic fields in these devices store and release reactive energy each AC cycle, causing current to lag behind voltage. Capacitive loads cause leading power factor (less common). Resistive loads (heaters, incandescent bulbs, electric kettles) have power factor close to 1.0. Modern LED drivers and variable-speed drives often include built-in PF correction.
Inverters are rated in kVA (apparent power) or kW (real power) — check which applies to your model. If an inverter is rated at 3,000W continuous, it can handle 3,000W of real power. But if your load has PF 0.7, the inverter must handle 4,286 VA of apparent power (3,000W ÷ 0.7). Most residential inverters can handle this, but check the kVA rating. Industrial inverters often specify both kW and kVA ratings separately.
For residential loads, PF 0.85+ is good; 0.95+ is excellent. Most modern appliances have PF 0.90-0.99 due to built-in PF correction. Older HVAC units, pool pumps, and well pumps may have PF 0.70-0.85. Commercial facilities with many motor loads sometimes install capacitor banks for PF correction to reduce utility demand charges. For off-grid systems, focus on the VA rating when sizing your inverter if you have significant motor loads.

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